A number is divisible by 5, if its units digit is 0 or 5.
Let n be any natural number. Then, n can be written as
n = 10a + b, where b is the units digit of n
Clearly, 10 is a multiple of 5. Therefore, 10a is also a multiple of 5.
The sum of any two multiples of 5 is a multiple of 5. Therefore, 10a+b will be a multiple of 5, if b is a multiple of 5.
Thus, an integer is divisible by 5, if its units digit is a multiple of 5. That is its units digit is either 0 or 5.
Hence the Test of Divisibility By 5 that is a number is divisible by 5, if its units digit is 0 or 5 is justified.
This implies that if the units digit of a number is not 0 or 5, then it is not divisible by 5.
In the general form since 10a is a multiple of 5. Therefore , when 10a + b is divided by 5, the remainder will be equal to the remainder when n is divided by 5.
Thus, the remainder when an integer is divided by 5 is equal to the remainder when its units digit is divided by 5.
Illustration : Write 521 in the form 10b + a then check its divisibility by 5
Solution: We will express 521 in the form 10b + a
where a = 1 and b = 52.
When 1 is divided by 5 it leaves a remainder as 1, So when 521 is divided by 5, the remainder is 1.
Check which of the following numbers are not divisible by 5? 1236055, 2525460, 1005670, 7898765 , 5689763, 5787984 | |||
Right Option : D | |||
View Explanation |
Write 221 in the form 10b + a then check its divisibility by 5. Find the value of a and b also. | |||
Right Option : D | |||
View Explanation |
Check which of the following numbers are not divisible by 5? 7837890, 2164672, 89270980, 8908770, 5264363, 67238765, 23564260,6754875 , 46467587, 78967643, 46587695, | |||
Right Option : C | |||
View Explanation |
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